Math
posted by Carmen
sin5x=cosx, find the general solutions for this please =)

drwls
Is that sin^5 x or sin(5x) on the left?
Respond to this Question
Similar Questions

Math
Verify the identity . (cscXcotX)^2=1cosX/1+cosX _______ sorry i cant help you (cscXcotX)=1/sinX  cosX/sinX = (1cosX)/sinX If you square this you have (1cosX)^2/(sinX)^2 Now use (sinX)^2 = 1  (cosX)^2 to get (1cosX)^2 / 1  … 
trig
it says solve for all real solutions, compute inverse functions to 4 sigfigs. cos^2x=35cosx Devon, what grade level are these questions from? 
maths
hey, i would really appreciate some help solving for x when: sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x 2sinxcosx  cosx = 0 cosx(2sinx  1)=0 cosx = 0 or 2sinx=1, yielding sinx=1/2 from cosx=0 and by looking … 
Math
How many solutions does the equation cosx + 1/2 = 1 have for 0<x<2pi cosx+1/2=1 cosx+1=2 cosx=21 cosx=1 therefore 1 solution? 
maths
find general solutions for sin5x=cosx 
Precalculus
Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π). 8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve algebraically for exact solutions in the interval [0,2π). Use your grapher only to support your … 
TRIGONOMETRY
Can someone please show me step by step solutions? 
Math, please help
Which of the following are trigonometric identities? 
Trigonometry
Can you please help me verify these? >sin7xsin5x= tanx(cos7xcos5x) >(1cosx)cot(1/2x) = sinx >1+tanx tan(x/2) = secx Its very confusing because of all the doublehalf angle formulas >_< 
Math
Find the solutions of sin5x + sin3x = 0 in the interval 0, 2pi. My answer: 0, pi/2, pi, 3pi/2