What is the magnitude of the average acceleration of a skier who, starting from rest, reaches a speed of 6.8 m/s when going down a slope for 2.5 s?
a=v/t
To find the magnitude (or absolute value) of the average acceleration of a skier, we need to use the formula:
average acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 0 m/s (starting from rest)
Final velocity (v) = 6.8 m/s
Time (t) = 2.5 s
Using the formula, we can calculate the magnitude:
average acceleration = (6.8 m/s - 0 m/s) / 2.5 s
average acceleration = 6.8 m/s / 2.5 s
average acceleration ≈ 2.72 m/s²
Therefore, the magnitude of the average acceleration of the skier is approximately 2.72 m/s².
To find the magnitude of average acceleration, we can use the formula:
average acceleration = change in velocity / time
In this case, the skier starts from rest, so the initial velocity (v₀) is 0 m/s. The final velocity (v) is given as 6.8 m/s. The time (t) is given as 2.5 seconds.
To find the change in velocity, we subtract the initial velocity from the final velocity:
change in velocity (Δv) = v - v₀
= 6.8 m/s - 0 m/s
= 6.8 m/s
Now, we can calculate the average acceleration:
average acceleration = Δv / t
= 6.8 m/s / 2.5 s
≈ 2.72 m/s²
Therefore, the magnitude of the average acceleration of the skier is approximately 2.72 m/s².