(x^2+11)/(3-x) x=4i

are you supposed to evaluate

(x^2+11)/(3-x) when x=4i?

If so, just plug it in:

((4i)^2+11)/(3-4i)
= (-16+11)/(3-4i)
= -5/(3-4i)
= -5(3+4i) / (3-4i)(3+4i)
= (-15 - 20i)/(9+16)
= -3/5 - 4/5 i