math
posted by NotGonnaSay .
An amount of $5000 is put into three investmesnts at rates of 6%, 7%, and 8% per annum, respectively. The total income is $358. The income from the first two investsments is $70 more than the third investment. Find the amount of each investment.

X at 6%
Y at 7%
Z at 8%
X + Y + Z = 5000
0.06X + 0.07Y + 0.08Z = 358
0.06X + 0.07Y  0.08Z = 70

Subtracting the last two equations tells you that 0.16Z = 288
Z = 1800.
X + Y = 3200
0.12X + 0.14Y = 428
Take it from there. Cheack my math 
X=1000. y= 2200 z =1800