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Chemistry

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At a certain temperature, .5 mol of PCl5 was placed in a .25 L vessel and permitted to react as shown

PCl5 (g) --> PCl3 (g)+ Cl2 (g)

At equilibrium, the container held .1 mol of PCl5. What is the value of "K"?

  • Chemistry -

    ........PCl5 ==> PCl3 + Cl2
    I.......0.5.........0.....0
    C........-x........x.......x
    E........0.5-x.......x.......x

    Therefore, mol PCl5 = 0.5-x = 0.1 and x = 0.4
    PCl3 = 0.4 mol
    Cl2 = 0.4 mol
    Convert mols to M = mols/L and substitute into K expression; solve.

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