algebra 2

posted by .

I am stuck this is how far I have gotten
x^2+6x=-1
(b/2)^2=(6/2)^2
=

  • algebra 2 -

    How far have you gotten? Copying and pasting the equations to solve? That's not too far.

    to solve polynomials, set everything on one side equal to zero:

    x^2 + 6x + 1 = 0
    try using the quadratic formula for this one.

    For the 2nd one, since you have basically,

    a^2 = b^2, just take the square roots:

    b/2 = 6/2
    or
    b/2 = -(6/2)

    That help?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    Please, can someone help? Evaluate log 1. This is my work up until I have gotten stuck: log 1 1=10^x I can't find a common base for 1 and 10^x. Wow, my apologies, this is algebra, not chemistry. but actually I think they use it in
  2. algebra 2

    solve the inequality: -3(r-11)+15> 9 _ this is as far as Ive gotten. -3r+33+15> 9 _ subtract 33, subtract 15 from each side. Now when you divide by -3, you have to reverse the inequality sign. Your answer will be r<something. …
  3. algebra problem that is causing me headaches

    I have no real method for this problem other than trail and error and foil. I have come up with some amny variations until I am on my second sheet of paper! The closet I have gotten to factoring/solving this problem so far is.... #46.) …
  4. Chemistry

    Dr. Bob ok well here is what i have gotten so far: on the problem H2O: 1.118 mol C2O4: .58681 mol Fe 3+: .2025 mol K^+: .3862 mol That is what ive gotten doing 20.14 g(1 mol / 18 g) = 1.118 mol and so on with the rest of them Did i …
  5. Algebra

    x^3-36x over x^2+7x+6, divided by 6x^2-x^3 over x^2+x I know the right answer is -1, but I can't seem to get to it. I've gotten as far as [x(x-6)]/1] * 1/[x^2(6-x)], which is then equal to [x(x-6)]/x^2(6-x). And then would I reduce …
  6. Algebra 1

    How would you solve the problem (w - 2)^2 ?
  7. calc - limits

    I have been trying to figure out these limit problems and I get stuck on trying to move the function around to make it possible to solve. The first one is: lim sinx - cosx / tanx - 1 x--> (pi/4) All I've gotten so far is to replace …
  8. English

    1. If I had studied hard, I could have gotten a higher score. 2. If I had studied hard, I could have gotten a better result. 3. If I had studied hard, I could have gotten a good/better grade. 4. If I had studied hard, I could not have …
  9. Algebra

    Factor 3x^3 + 9x^2 - 3x - 9 3x^3 + 9x^2 - 3x - 9 3 (x^3 + 3x^2- x - 3) 3 ( x+3x^2) ( -x - 3) 3 {x( 1 + 3x) -1 (x -1) This is a far I have gotten. Can someone please help me through the rest of the answer?
  10. Algebra

    5x+3y=9x-7y I am having trouble in solving. My answer is ending in fractions. And do far I have gotten y=-1/7

More Similar Questions