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the end points of a line segment are A (-7, -1) and B (5,5)

determine the equation of right bisector of AB

show that the origin 0,0 lies on the right bisector of AB

  • math -

    slope of AB = 6/12 = 1/2
    slope of right bisector = -2
    midpoint of AB = (-1,2)
    equation of right-bisector
    y-2 = -2(x+1)
    y-2 = -2x - 2
    y - 2x

    it is obvious that (0,0) satisfies this equation, thus (0,0) lies on this line

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