Explain what would happen when bromine water is added to potassium iodide solution and what is its balanced chemical equation?
Bromine oxidizes the iodide ion to I2 and is reduced to Br^-.
Br2 + 2KI ==> I2 + 2KBr.
When bromine water is added to potassium iodide solution, a redox reaction takes place, resulting in the formation of potassium bromide (a salt) and iodine (a solid).
Here is the balanced chemical equation for the reaction:
2KI (aq) + Br2 (aq) → 2KBr (aq) + I2 (s)
Let's break down the steps of the reaction:
Step 1: Dissociation
The potassium iodide (KI) dissociates in water to form potassium ions (K+) and iodide ions (I-).
KI (aq) → K+ (aq) + I- (aq)
Step 2: Addition of bromine water
When bromine water (Br2 dissolved in water) is added to the solution, the bromine (Br2) molecules react with the iodide ions (I-) present in the solution.
Step 3: Redox reaction
In the reaction, bromine (Br2) is reduced, meaning it gains electrons, and iodide ions (I-) are oxidized, meaning they lose electrons. This results in the formation of potassium bromide (KBr) and iodine (I2).
Step 4: Formation of products
The reaction forms potassium bromide (KBr), which remains dissolved in the solution as potassium ions (K+) and bromide ions (Br-). It also generates iodine (I2) as a solid precipitate. The iodine appears as a dark-colored solution or solid in the reaction mixture.
Overall, the reaction between bromine water and potassium iodide solution results in the formation of potassium bromide and free iodine.
When bromine water (a solution of bromine in water) is added to potassium iodide (KI) solution, a reaction occurs known as a displacement reaction. In this reaction, the more reactive bromine replaces iodine in the potassium iodide solution, resulting in the formation of potassium bromide (KBr) and iodine (I2).
The balanced chemical equation for the reaction can be represented as follows:
Br2 + 2KI -> 2KBr + I2
In this equation, the bromine (Br2) molecules react with the potassium iodide (2KI) molecules to produce two molecules of potassium bromide (2KBr) and one molecule of iodine (I2). Each side of the equation has an equal number of atoms, ensuring that the law of conservation of mass is upheld.
Visually, you would observe the bromine water, which has a reddish-brown color, turning into a yellowish-brown color as the iodine forms. The solution may also become cloudy due to the formation of solid iodine. Additionally, the potassium iodide solution may appear to lighten in color as the reaction progresses.