a delivery truck is 5 km away from a car. the two started at the same time and headed at the same direction. the delivery truck accelerates at 3m/s. if the car should overtake the truck in ten minutes, what should be the acceleration of the car?
Do you mean 3m/s^2?
Please check your INFO.
thats 3 m/s^2. this is exactly the same problem that we are ask to solve.
Answer pls
To find the acceleration of the car, we can use the equation of motion that relates distance, time, initial velocity, and acceleration. The equation is:
Distance = Initial Velocity * Time + (1/2) * Acceleration * Time^2
Let's start by converting the time from minutes to seconds since the velocity and acceleration use SI units.
Given:
Initial distance, D = 5 km
Acceleration of the truck, A_truck = 3 m/s^2
Time, t = 10 minutes = 10 * 60 seconds = 600 seconds
Since both the truck and car started at the same time, let the initial velocity of both the truck and the car be V_initial.
Now, we can write the equation for the truck:
Distance_truck = V_initial * t + (1/2) * A_truck * t^2
Considering the car overtakes the truck, the distance covered by the car will be the same as the distance covered by the truck. So, we can also write the equation for the car:
Distance_car = V_initial * t + (1/2) * A_car * t^2
Since both the truck and car travel in the same direction, the car's velocity will be greater than the truck's velocity.
Therefore, Distance_truck = Distance_car
Plugging in the values and simplifying the equation, we have:
V_initial * t + (1/2) * A_truck * t^2 = V_initial * t + (1/2) * A_car * t^2
Since V_initial * t cancels out on both sides, we can solve for the acceleration of the car:
(1/2) * A_truck * t^2 = (1/2) * A_car * t^2
Divide both sides by (1/2) * t^2:
A_truck = A_car
Therefore, the acceleration of the car should be 3 m/s^2, the same as the acceleration of the truck.