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math 213

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The amount of money in cents in a jar containing some nickels and d dimes and some quarters if there are 4 times as many nickels as dimes and twice as many quarters as nickels

  • math 213 -

    there are:
    d dimes
    4d nickels
    2*4d = 8d quarters, so

    cents = 10d + 5(4d) + 25(2(4d)) = 10d+20d+200d = 230d

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