math 213
posted by susan .
The amount of money in cents in a jar containing some nickels and d dimes and some quarters if there are 4 times as many nickels as dimes and twice as many quarters as nickels

there are:
d dimes
4d nickels
2*4d = 8d quarters, so
cents = 10d + 5(4d) + 25(2(4d)) = 10d+20d+200d = 230d