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A 45 g superball traveling at 28.0 m/s bounces off a brick wall and rebounds at 24.5 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 3.60 ms, what is the magnitude of the average acceleration of the ball during this time interval? (Note: 1 ms = 10-3 s.)

Please show the work and the answer. Thanks so much!!

  • physics -

    a = (V-Vo)/t.
    a = (24.5-0) / 0.0036 = 6806 m/s^2.

  • physics -

    Nope, Henry. Vo=-28

    a= (24.5+28)/1E-3

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