# Algebra2

posted by .

1.30√-25 x 8√-49

2. 6√-64 + 12√-36

3. 4√-13 - 6√-13

• Algebra2 -

30√-25 x 8√-49
= 30√25√-1 x 8√49√-1
=150√-1 x 56√-1
= 8400 (-1)
= -8400 , remember that √-1 x √-1 = i x i = i^2 = -1

do the others the same way, let me know what you got

• Algebra2 -

I'm Doing Problem 2 Right Now .
But I'm Stuck How Did You Get 150 In the 3rd Line?

• Algebra2 -

30√25√-1 x 8√49√-1
= 30 x 5 x √-1 x 8 x 7 x √-1
= 150 x √-1 x 56 x √-1
= 8400 x i^2
= ....

• Algebra2 -

Oh Okay .
I Tried The Other Two Problems.
For #1 I Got 120 As My Answer.
For #2 I Got 37 As My Answer.

• Algebra2 - Sara -

Nope:

6√-64 + 12√-36 = 6*8i + 12*6i = 120i

4√-13 - 6√-13 = (4-6)√-13 = -2√13 i

## Similar Questions

1. ### Algebra

How would i complete these problems? 1. (√6mn)^5 2. ^3√16x - ^3√2x^4 3.^4√x • ^3√2x 4. ^3√72x^8 5. √63a^5b • √27a^6b^4 and are these problems correct?
2. ### Math

Find an equation of the line that bisects the obtuse angles formed by the lines with equations 3x-y=1 and x+y=-2. a. (3√2 +√10)x-(√10 + √2)y-2√10+√2=0 b. (3√2 - √10)x+(√10 - √2)y+2√10+√2=0 …
3. ### maths

I will be thankfull to you if you help me to solve the below problem: 6√x-11/3√x=2√x+1/√x+6 I tried to solve the above problem like this: (6√x-11)(√x+6)=(3√x)(2√x+1) 6√x(√x+6)-11(√x+6)=(3√x)(2√x)+(3√x)(1) …
4. ### Algebra Work Check

1. 5√6 * 1/6√216 5/6 * √1296 5/6 * √144 * √9 = 30 2. -9√28a^2 * 1/3√63a -3√1764a^3 -3√49a^2 * √36a -3*7a*6√a = -126a√a
5. ### Algebra 2 Answer Check

Simplify by rationalizing each denominator. 1. 2/√3 A: 2√3 / 3 2. -18/√6 A: -3√6 Add or subtract. 3. 4√3 - 9√3 A: -5√3 4. √8 - 15√2 A: -13√2 5. √45 + √20 A: 5√5 …