Calculus
posted by Rich .
Find the first 6 terms of the sequence b^1 = 5. B^n = 2b(n 1) when n>1. Then write an explicit definition of the sequence and use it to find the 12th term.

Bn = 5*2^(n1)
B12 = 5*2^11 = 10240
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Quick math help
Find the tenth term of the sequence: 6,1,8... Is it 57?