posted by Mr. Desperate .
A car is travelling at 30.0 mi/h (13.41 m/s) on a level road where the coefficient of static friction between its tires and the road is 0.70. Find the minimum turning radius of the car.
Since the road is level (unbanked), the maximum friction force M*g*Us must equal the centripetal force M V^2/R, at minimum turning radius.
R = V^2/(g*Us) = (13.41)^2/(9.8*0.70)
= 26.2 meters