A student needed to determine the percent composition of a mixture that contained fluorene and benzoic acid. The student took 245 mg of the mixture and used the extraction method to separate the components. Then both compounds were recrystallized and dried. The experiment produced 103 mg of fluorene and 105 mg of benzoic acid. Calculate the percent composition of the mixture.
Does the mixture contain impurities as well as fluorene and benzoic acid?
Do you know the solubility of fluorene and benzoic acid.
Are you to assume 100% yield?
I have the same question and it doesn't have any impurities.
To determine the percent composition of the mixture, we need to calculate the mass of each compound and then express it as a percentage of the total mass of the mixture.
First, let's calculate the mass of fluorene in the mixture:
Mass of fluorene = 103 mg
Next, let's calculate the mass of benzoic acid in the mixture:
Mass of benzoic acid = 105 mg
Now, let's calculate the total mass of the mixture:
Total mass of the mixture = Mass of fluorene + Mass of benzoic acid
= 103 mg + 105 mg
= 208 mg
Finally, let's calculate the percent composition of each compound in the mixture:
Percent composition of fluorene = (Mass of fluorene / Total mass of the mixture) * 100
= (103 mg / 208 mg) * 100
≈ 49.51%
Percent composition of benzoic acid = (Mass of benzoic acid / Total mass of the mixture) * 100
= (105 mg / 208 mg) * 100
≈ 50.49%
Therefore, the percent composition of the mixture is approximately 49.51% fluorene and 50.49% benzoic acid.