Find the speed at which water travels in a pipe if the height is

a. 5cm. b. 8cm. c. 18 cm.
[Use the formula v^2=1960(h+10).]

I do no recognize where the +10 term comes from. What height h are they talking about? It probably has something to do with the vertical height of the water surface above the outlet.

Evidently they want you to substitute 5 cm for h in part (a) and solve for v. It will be in cm per second.

Then do it again with h = 8 cm and h = 18 cm.

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To find the speed at which water travels in a pipe, we can use the given formula: v^2 = 1960(h + 10), where v is the speed and h is the height.

a. When the height is 5cm:
Plug in the value of h into the formula:
v^2 = 1960(5 + 10)
Simplify:
v^2 = 1960(15)
Divide both sides by 1960:
v^2 / 1960 = 15
Square root both sides to solve for v:
v = √(15)
Therefore, the speed of water is approximately √(15) cm.

b. When the height is 8cm:
Plug in the value of h into the formula:
v^2 = 1960(8 + 10)
Simplify:
v^2 = 1960(18)
Divide both sides by 1960:
v^2 / 1960 = 18
Square root both sides to solve for v:
v = √(18)
Therefore, the speed of water is approximately √(18) cm.

c. When the height is 18cm:
Plug in the value of h into the formula:
v^2 = 1960(18 + 10)
Simplify:
v^2 = 1960(28)
Divide both sides by 1960:
v^2 / 1960 = 28
Square root both sides to solve for v:
v = √(28)
Therefore, the speed of water is approximately √(28) cm.

So, the speeds of water for the given heights are approximately √(15) cm, √(18) cm, and √(28) cm respectively.