Concentrated hydrochloric acid has specific gravity 1.18 and 36% hcl weight. What volume of concentrated hcl must be diluted to give 50gm of 10 percent
My calculation
50gm x 10% = 5gm
5gm x 36.46 =182.3/ 0.36 =
506 / 1.18 = 429 ml
I am not sure answer. Who helps me to solve it for me. Thank you.
I worked this for you a day or so ago (two ways in fact) so you should know 429 mL is not right.In the future I will ignore any problems I've addressed previously.
g x % = g x %
50g x 10% = g x 36%
g = (50*10/36) = 13.89g.
Use density = mass x volume to convert 13.89g to mL.
v = m/d = 13.89/1.18 = 11.77 mL which I would round to 11.8 mL.
You can prove this is right as follows:
1.18g/mL x ?mL x 0.36 = 5g
?mL = 11.77
The other way to do this is by parts.
You want to dilute from 36^ to 10% which is a factor of 36/10 = 3.6. Therefore, you want to dilute 1 part acid with 2.6 parts water to make the solution. How much is 1 part? That's 50g/3.6 = 13.89 g which converts to 11.77 mL.
To solve the problem, you need to calculate the volume of concentrated HCl required to obtain a solution with a concentration of 10%. Here's a step-by-step breakdown of the calculation:
1. Start by converting the mass of HCl required to grams. In this case, you have 50 grams of a 10% HCl solution, so the mass of HCl can be calculated as follows:
Mass of HCl = 50 grams x 0.10 = 5 grams
2. Convert the mass of HCl from grams to moles using the molar mass of HCl, which is approximately 36.46 grams/mole. The formula for this conversion is:
Moles of HCl = Mass of HCl / Molar mass of HCl = 5 grams / 36.46 grams/mole ≈ 0.137 moles
3. Determine the volume of concentrated HCl required to obtain 0.137 moles of HCl. Since the concentration of the concentrated HCl is 36% by weight, you can use the formula:
Volume of concentrated HCl = Moles of HCl / Concentration of HCl = 0.137 moles / 0.36 = 0.381 L
4. Finally, convert the volume from liters to milliliters by multiplying by 1000:
Volume of concentrated HCl = 0.381 L x 1000 = 381 mL
So, the volume of concentrated HCl that must be diluted is approximately 381 mL.