Assume that the ionic compound CaCl2, separates completely into Ca and Cl ions when it dissolves in water. How many moles of each ion are present in the solution???
It all depends upon how many grams CaCl2 you dumped into the solution doesn't it? Certainly.
1 mol CaCl2 gives you 1 mol Ca ions and 2 mols Cl ions.
To determine the number of moles of each ion in the solution, we need to consider the chemical formula of CaCl2.
The formula tells us that for every molecule of CaCl2 that dissolves, it separates into one Ca2+ ion and two Cl- ions.
Since the ionic compound CaCl2 is completely separated into its ions when it dissolves, we can conclude that for every one mole of CaCl2, we will have one mole of Ca2+ ions and two moles of Cl- ions.
Therefore, the number of moles of each ion in the solution is as follows:
- One mole of Ca2+ ions
- Two moles of Cl- ions.
To determine the number of moles of each ion present in the solution, we need to consider the chemical formula of CaCl2 and the concept of stoichiometry.
The chemical formula CaCl2 indicates that for every one CaCl2 molecule, it dissociates into one Ca2+ ion and two Cl- ions.
Since the compound has separated completely, we can assume that one mole of CaCl2 has dissociated to produce one mole of Ca2+ ions and two moles of Cl- ions.
Therefore, the number of moles of Ca2+ ions in the solution would be equal to the number of moles of CaCl2 that dissolved, while the number of moles of Cl- ions would be twice the number of moles of CaCl2.
To find the number of moles present, you would need to know the amount (in grams or moles) of CaCl2 that was dissolved in the water.