How many grams of CaSO4 are present in 320ml of a 0.00810 M solution of this compound?
How many mols do you have? That's M x L = mols = ?
grams = mols x molar mass = ?
Answer is .3525 grams?? Thanks
To find the number of grams of CaSO4 present in the solution, you need to use the molarity (M) of the solution and the volume of the solution.
Here are the steps to calculate it:
1. Convert the volume of the solution from milliliters (ml) to liters (L):
320 ml ÷ 1000 = 0.320 L
2. Use the formula for molarity:
Molarity (M) = moles of solute ÷ volume of solution (in liters)
Rearrange the formula to calculate the moles of solute:
Moles of solute = Molarity (M) × volume of solution (in liters)
Moles of solute = 0.00810 M × 0.320 L
3. Calculate the moles of CaSO4:
Since one mole of CaSO4 has a molar mass of 136.14 g/mol, you can calculate the moles of CaSO4:
Moles of CaSO4 = Moles of solute × Molar mass of CaSO4
Moles of CaSO4 = (0.00810 M × 0.320 L) × (136.14 g/mol)
4. Finally, calculate the grams of CaSO4:
Grams of CaSO4 = Moles of CaSO4 × Molar mass of CaSO4
Grams of CaSO4 = (0.00810 M × 0.320 L) × (136.14 g/mol)
Now you can plug in the values and calculate the result.