Concentrated hydrochloric acid has specific gravity of 1.18 and 36% hcl weight. What volume of concentrated hcl must be diluted to give 50 gm of 10 percent.

My calculation
50gm x 0.1 = 5gm
5gm x 36.5 = 182.5
182.5 / 0.36 = 506.9
506.9 / 1.18 = 430 ml This is answer. I am not sure answer. Please help

I don't think 430 mL is correct.

There a couple ways of doing this. I prefer the first one.
g x % = g x %
50 x 10 = g x 36
g = 13.9 g.
Then use density to convert to volume.
v = m/d = 13l.9/1.18 = ?

OR
You want to dilute 36% to 10% which is a factor of 36/10 = 3.6 or
1 part stock + 2.6 parts H2O
How much is 1 part? That is 50/3.6 = 13.9g and convert that to volume using density.

To find the volume of concentrated hydrochloric acid (HCl) that must be diluted to give 50g of a 10% solution, you need to use the given information on specific gravity and HCl weight.

Here's a step-by-step explanation of how to calculate the answer:

1. Calculate the weight (in grams) of HCl required in the 10% solution:
50g x 0.1 = 5g

2. Convert the weight of HCl to moles by dividing by the molar mass of HCl:
5g HCl / 36.5 g/mol = 0.137 mol HCl

3. Determine the volume (in liters) of the 10% solution using the equation:
Volume (in liters) = Moles / Concentration
Volume = 0.137 mol HCl / 0.1 = 1.37 liters (since a 10% solution by weight is equivalent to 10g HCl dissolved in 100g of solution)

4. Convert the volume from liters to milliliters:
1.37 liters x 1000 mL/liter = 1370 mL

So, you would need to dilute approximately 1370 mL of concentrated hydrochloric acid to obtain 50g of a 10% solution.

It seems like your initial calculation is incorrect. The correct answer is not 430 mL, but rather 1370 mL.