A machine has a work output of 28ax^5 joules and a work input of 7a^2x^6 joules. What is the efficiency of the machine?
Eff. = Output/Input.
Eff.=28ax^5 / 7a^2x^6 =4a^-1x^-1=4/ax
To find the efficiency of a machine, we need to calculate the ratio of the work output to the work input. Efficiency is defined as the ratio of useful work output to the total work input.
In this case, the work output is given as 28ax^5 joules, and the work input is given as 7a^2x^6 joules.
The efficiency can be represented by the formula:
Efficiency = (Work output / Work input) * 100%
Substituting the given values:
Efficiency = (28ax^5 / 7a^2x^6) * 100%
Now, let's simplify the expression:
Efficiency = (4x^(-1) / a) * 100%
Efficiency = 4x^(-1) * 100% / a
Finally, the efficiency of the machine is 4x^(-1) * 100% / a, where x and a are variables representing the given values.