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Prove that sin^2(Omega) - Cos^2(Omega) / tan(Omega) sin(Omega) + cos(Omega) tan(Omega) = cos(Omega) - cot (Omega) cos (omega)
If could explain, please. That would be great (:
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symbolab(dot com) helps a ton with proving trigonometric identities. its a calculator, but it shows the steps and whatnot.
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Prove that sin^2(Omega) - Cos^2(Omega) / tan(Omega) sin(Omega) + cos(Omega) tan(Omega) = cos(Omega) - cot (Omega) cos (omega)
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This has been answered. See related links below
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Prove that sin^2(Omega) - Cos^2(Omega) / tan(Omega) sin(Omega) + cos(Omega) tan(Omega) = cos(Omega) - cot (Omega) cos (omega)
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I had answered this for you earlier http://www.jiskha.com/display.cgi?id=1344303115 Please check
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PLEASE someone check these for me, Thanks..
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and the period equals two pi over omega 40 min = (2pi)/omega omgea = pi/20
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