Trigonometry
posted by Marie .
Prove that 1+tan(Theta)/1tan(Theta) = sec^2(Theta)+2tan(Theta)/1tan^2(Theta)
If you explain, that would be great (:

(1+tan)/(1tan)
multiply top and bottom by 1+tan
(1+tan)^2 / (1tan)(1+tan)
(1 + 2tan + tan^2)/(1tan^2)
now, since sec^2 = 1+tan^2,
(sec^2 + 2tan)/(1tan^2)
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