what net force is required to bring a 1500kg car to rest from a speed of 100kph within a distance of acceleration.

First you have to tell us what the stopping distance or stopping time is. You seem to have left that out.

That will enable you to calculate the acceleration, a.

Then use F = m a fr the stopping force.

To determine the net force required to bring a car to rest from a given speed within a specific distance, we need to use the principles of Newton's laws of motion and the equations of motion.

First, we need to convert the car's initial speed from 100 km/h to meters per second (m/s). We know that 1 km/h is equal to 0.2778 m/s, so multiplying the initial speed by this conversion factor, we get:

Initial speed = 100 km/h * 0.2778 m/s/km/h = 27.78 m/s

Next, we need to calculate the acceleration required to bring the car to rest using the equation of motion:

v^2 = u^2 + 2as

where:
v = final velocity (0 m/s because the car comes to rest)
u = initial velocity (27.78 m/s)
a = acceleration
s = distance

Rearranging the equation to solve for acceleration (a) gives us:

a = (v^2 - u^2) / (2s)

Substituting the values into the equation:

a = (0^2 - 27.78^2) / (2s)
a = (-27.78^2) / (2s)
a = -769.68 / (2s)
a = -384.84 / s

Now that we have the acceleration, we can calculate the net force required using Newton's second law of motion, which states that:

Force = mass * acceleration (F = ma)

Given that the mass of the car is 1500 kg, we can substitute the values:

Force = 1500 kg * (-384.84 / s)
Force = -577,260 / s

Based on this calculation, the net force required to bring the 1500 kg car to rest from a speed of 100 km/h within a distance of acceleration units would be approximately -577,260 / s Newtons, where 's' represents the distance. Note that the negative sign indicates that the force acts in the opposite direction to the car's motion, which is necessary to bring it to rest.