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If I have cards numbered 1 through 40 and I randomly draw 3 then replace them, shuffle them and draw three again what are the odds of drawing one of the numbers more than once

  • Math -

    The first three cards are irrelevant.
    For the second draw, the
    p=P(repeat at least once)
    = 1-P(no repeat at all)
    =1 - (37*36*35)/(40*39*38)

    Odds: p : (1-p) = 211/988: 777/988
    = 211 : 777

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