posted by Melanie .
suppose that sin0=-5/13 and that 0 is a quadrant III angle. what is the exact value of cos0
The "reference angle" that theta makes with the -x axis is sin^-1(5/13) . The cosine of that angle is 12/13.
(Think of a 5:12:13 right triangle)
Cosine is negative in the third quadrant.
The answer is -12/13
make a sketch of the right-angled triangle in quad III, with hypotenuse 13 and opposite 5.
By Pythagoras the adjacent would be 12 (the 5-12-13 triangle)
so cosØ = -12/13 ( by CAST, in III the cosine is negative)