physic
posted by Anonymous .
A grinding wheel of radius 0.280 m rotating on a frictionless axle is brought to rest by applying a constant friction force tangential to its rim. The constant torque produced by this force is 75.3 N ยท m. Find the magnitude of the friction force.

(friction force) * (radius) = torque
Solve for the friction force, in Newtons.
75.3/0.28 = ___ N 
Torque=r x friction
so...solve for friction for
torque is known:75.3 Nm
radius is known:0.280m
so Torque/radius=75.3Nm/0.280m
meters cancel out =269N