Post a New Question


posted by .

A grinding wheel of radius 0.280 m rotating on a frictionless axle is brought to rest by applying a constant friction force tangential to its rim. The constant torque produced by this force is 75.3 N ยท m. Find the magnitude of the friction force.

  • physics -

    (friction force) * (radius) = torque

    Solve for the friction force, in Newtons.

    75.3/0.28 = ___ N

  • physic -

    Torque=r x friction
    so...solve for friction for

    torque is known:75.3 Nm
    radius is known:0.280m

    so Torque/radius=75.3Nm/0.280m
    meters cancel out =269N

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question