What volume (L) of a 3M KOH solution can be prepared by diluting 0.5 L of a 5M KOH solution?
M x L = M x L
3M x ?L = 5M x 0.5L
Solve for L
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To find the volume of a 3M KOH solution that can be prepared by diluting 0.5 L of a 5M KOH solution, we can use the concept of dilution.
Dilution is the process of reducing the concentration of a solute in a solution by adding more solvent. In this case, we want to dilute the 5M KOH solution to a concentration of 3M.
The formula for dilution is:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
Let's plug in the given values into the formula:
C1 = 5M
V1 = 0.5L
C2 = 3M
V2 = ?
5M * 0.5L = 3M * V2
2.5 = 3V2
V2 = 2.5 / 3
V2 ≈ 0.833 L
Therefore, approximately 0.833 liters of a 3M KOH solution can be prepared by diluting 0.5 L of a 5M KOH solution.