Physics
posted by Beth .
When uranium 92U235 decays, it emits a ray. If the emitted ray has a wavelength of 1.30 x 1011 m, determine the energy (in MeV) of the ray

ε=hc/λ=
=6.63•10^34•3•10^8/1.3•10^11=
=1.53•10^14 J =1.53•10^14/1.6•10^19=
=95625 eV=0.095625 MeV
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