Math
posted by Bianca .
The length of a rectangle is 2 more than twice its width. If the area of the rectangle is 24 sq. m., find its dimensions.

L = 2 + 2 W = 2 ( 1 + W )
A = L * W
24 = 2 * ( 1 + W ) * W
24 = 2 * ( W + W ^ 2 ) Divide both sides by 2
12 = W + W ^ 2 Subtract 12 to both sides
0 = W + W ^ 2  12
Now you must solwe equation :
W ^ 2 + W  12 = 0
The exact solutions are 3 and  4
Width cannot be negative so W = 3 m
L = 2 + 2 W
L = 2 + 2 * 3
L = 2 + 6 = 8 m
A = L * W = 8 * 3 = 24 m ^ 2
P. S.
If you don't know how to solve equations :
W ^ 2 + W  12 = 0
in google type: quadratic equation online
When you see list of results click on:
Free Online Quadratic Equation Solver:Solve by Quadratic Formula
When page be open in rectangle type:
W ^ 2 + W  12 = 0
and click option: solve it!
You wil see solution stepbystep
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