# chem

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Cesium-137 has a half life of 30.0 years. If initially there are 8.0 kg of cesium-137 present in a sample, how many kg will remain after 60.0 years?

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k = 0.693/t1/2 and substitute k into the equation below.

ln(No/N) = kt
No = 8 kg
N = ?
k from above
t = 60.0 years.

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