what are the number of moles of phosphorus in 15 moles of Ca3(PO4)2
To determine the number of moles of phosphorus (P) in Ca3(PO4)2, we need to consider the chemical formula of the compound. Ca3(PO4)2 consists of three calcium (Ca) atoms, two phosphate (PO4) groups, and one phosphorus (P) atom in each phosphate group.
Since there are two phosphate groups in the compound, the number of phosphorus atoms is equal to 2. Therefore, to find the number of moles of phosphorus in 15 moles of Ca3(PO4)2, we can multiply 15 moles by the number of phosphorus atoms in one mole of Ca3(PO4)2.
The molar ratio of phosphorus to Ca3(PO4)2 is 2:1. This means that for every 2 moles of phosphorus atoms, we have 1 mole of Ca3(PO4)2.
To calculate the number of moles of phosphorus in 15 moles of Ca3(PO4)2, we can set up the following proportion:
(Number of moles of phosphorus) / (Number of moles of Ca3(PO4)2) = (Number of phosphorus atoms) / (Number of Ca3(PO4)2 units)
Knowing that there are 2 moles of phosphorus atoms in 1 mole of Ca3(PO4)2, we can set up the equation as:
(Number of moles of phosphorus) / 15 = 2 / 1
Now we can solve for the number of moles of phosphorus:
(Number of moles of phosphorus) = (2 / 1) * 15
(Number of moles of phosphorus) = 30
Therefore, there are 30 moles of phosphorus in 15 moles of Ca3(PO4)2.