Algebra
posted by Anna .
Divide and check:
(3x^22x13)divided by (x2)

(3x^2  2x  13) / (x2) = (3x + 4),
5 Remainder.
Long division was used, but it is difficult to show here.
Check:
(x2)(3x+4) =
3x^2 + 4x 6x  8 =
(3x^2  2x 8) 5 = 3x^2  2x  13.
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