Post a New Question

Algebra

posted by .

Divide and check:
(3x^2-2x-13)divided by (x-2)

  • Algebra -

    (3x^2 - 2x - 13) / (x-2) = (3x + 4),
    -5 Remainder.

    Long division was used, but it is difficult to show here.

    Check:

    (x-2)(3x+4) =
    3x^2 + 4x -6x - 8 =
    (3x^2 - 2x -8) -5 = 3x^2 - 2x - 13.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question