H3PO4 reagent solution in a lab is 85%pure.specific gravity of H3PO4 solution is 1.69.find out the normality of H3PO4.
Technically the normality can't be determined without knowing the reaction involved. The equivalent weight could be molar mass/1, molar mass/2, or molar mass/3 depending upon the replacement of 1, 2, or 3 of the hydrogen atoms. The usual answer is molar mass/3
First I would find the molarity.
1.69g/mL x 1000 mL x 0.85 = ? g H3PO4 in 1 L of solution.
mols H3PO4 = g/molar mass and that will be the molarity.
Then N = 3*M
To find the normality of H3PO4, we need to consider the purity of the H3PO4 reagent solution and its specific gravity.
Normality (N) is defined as the number of equivalents of a solute dissolved per liter of solution. In the case of H3PO4, we can determine the normality by taking into account its molecular weight and the concentration of the solution.
First, let's find the molecular weight of H3PO4:
H3PO4 consists of 3 hydrogen (H) atoms, 1 phosphorus (P) atom, and 4 oxygen (O) atoms.
The atomic masses are approximately:
H = 1
P = 31
O = 16
So, the molecular weight of H3PO4 can be calculated as:
(3 x 1) + 31 + (4 x 16) = 98 g/mol
Now, let's calculate the concentration (in grams per liter) of H3PO4 in the solution, taking into account its purity and specific gravity:
Given that the H3PO4 reagent solution is 85% pure, this means that for every 100 grams of the solution, 85 grams of it is H3PO4. Thus, the concentration of H3PO4 is 85 grams per 100 grams of solution.
Since specific gravity is the ratio of the density of a substance to the density of a reference substance, we can use it to calculate the concentration.
In this case, the specific gravity of the H3PO4 solution is 1.69. This means the solution is 1.69 times denser than water.
Since 1 liter of water weighs approximately 1000 grams, the weight of 1 liter of the H3PO4 solution can be calculated as:
1 liter x 1.69 = 1690 grams
Thus, the weight of the H3PO4 in the 1 liter of solution is:
(85/100) x 1690 = 1436.5 grams
Now we have all the necessary information to calculate the normality:
Normality (N) = (Weight of Solute in grams / Molecular Weight of Solute) / Volume of Solution in liters
N = (1436.5 g / 98 g/mol) / 1 L
N ≈ 14.66 N
Therefore, the normality of the H3PO4 solution is approximately 14.66 N.