a car travels 30 km due north and 40 km due east .how far is it from the startin point?

Since this is asking for the hypotenuse of a right triangle, use the Pythagorean Theorem.

a^2 + b^2 = c^2

Solution:

sqrt of (30)^2+(40)^2= 50km

To find the distance from the starting point after a car travels 30 km due north and 40 km due east, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the car's route forms a right triangle. The northward distance of 30 km represents one side, and the eastward distance of 40 km represents the other side. The distance from the starting point is the hypotenuse.

To find the distance, we can use the formula:
distance = √(northward distance^2 + eastward distance^2)

Plugging in the values:
distance = √(30 km^2 + 40 km^2)

Calculating:
distance = √(900 km^2 + 1600 km^2)
distance = √(2500 km^2)
distance = 50 km

Therefore, the car is 50 km from the starting point.

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