an object a is moving with 10m/s and bis moving with 5m/s in the same direction of positive x axis . ais 100 m behind b . find time taken by a to meet b
(100+x)/v(A) = x/v(B)
500+5x=10x
x=100 m
t=(100+x)/v(a)=200/10=20 s.
To find the time taken by object A to meet object B, we need to consider their velocities and the initial distance between them.
Given:
Velocity of object A (Va) = 10 m/s
Velocity of object B (Vb) = 5 m/s
Initial distance between A and B (d) = 100 m
Since both objects are moving in the same direction, we can find their relative velocity by subtracting the velocity of B from the velocity of A:
Relative velocity (Vr) = Va - Vb
= 10 m/s - 5 m/s
= 5 m/s
Now, we can use the formula for time:
Time (t) = Distance (d) / Relative velocity (Vr)
Plugging in the values:
t = 100 m / 5 m/s
t = 20 seconds
Therefore, it will take object A 20 seconds to meet object B.