Solve. Leave the answers in terms of pi ?.

a)Find a polynomial for the sum of the areas of the circles shown in the figure.
b)Find the sum of the areas when r = 5 and r = 11.3.
this is what I got but I did not do it right. I needed to To write an expression for the sum, i need to put everything together by adding the three terms that i wrote below but not sure how to start.
(pi*r2)+(pi*r2)
(pi*52)+(pi*11.32)
(25pi)+(127*69pi)
(152.69pi)
Large circle: A=pi*r2, Medium circle A=pi*32, Small circle A=pi*22

To solve this problem, you need to find a polynomial expression for the sum of the areas of the circles and then evaluate it for the given values of r.

a) First, let's find the area of each circle:
- The area of the large circle with radius r is given by A1 = πr^2.
- The area of the medium circle with radius 3 is given by A2 = π(3^2) = 9π.
- The area of the small circle with radius 2 is given by A3 = π(2^2) = 4π.

To find the sum of the areas of all three circles, you need to add these expressions together:

A_sum = A1 + A2 + A3
= πr^2 + 9π + 4π
= π(r^2 + 13)

So, the polynomial expression for the sum of the areas of the circles is A_sum = π(r^2 + 13).

b) Now, let's substitute the values given in part b into the polynomial expression:

For r = 5:
A_sum = π(5^2 + 13)
= π(25 + 13)
= π(38)
= 38π

For r = 11.3:
A_sum = π(11.3^2 + 13)
= π(127.69 + 13)
= π(140.69)
= 140.69π

So, the sum of the areas when r = 5 is 38π, and when r = 11.3 is 140.69π.