A person shouts in a canyon. 3 s later they hear the echo. How far away is the canyon wall from which the sound wave was reflected?

how do i do this problem?

distance=velocity*time

2*canyonwidth=speedsound*time

solve for canyon widthhttp://www.ausetute.com.au/calcelemf.html

2cw=340*3/2=510m but the answer given is 514.5m?

Sound waves move through air at sea level at a velocity of 343 m/s at 20ºC.

x=343•3/2=514.5 m

To solve this problem, we can use the speed of sound and the time it takes for the echo to reach the person. The speed of sound in air is approximately 343 meters per second.

Let's break down the problem step by step:

1. Start by looking at the time it takes for the echo to reach the person. In this case, the time is given as 3 seconds.

2. Since the person hears both the original shout and the echo, the sound travels to the wall and back to the person's ears. Therefore, the total distance the sound wave traveled is twice the distance between the person and the wall.

3. To find the distance, we can use the formula: Distance = Speed × Time. Since the sound traveled twice the distance, the formula becomes: Distance = 2 × Speed × Time.

4. Plug in the values: Distance = 2 × 343 m/s × 3 s.

5. Calculate the result: Distance = 2058 meters.

Therefore, the canyon wall from which the sound wave was reflected is approximately 2058 meters away from the person.

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