practical math
posted by Anonymous .
A quantity of gas has a volume of 0.20 cubic meter and an absolute temperature of 333 degrees kelvin. When the temperature of the gas is raised to 533 degrees kelvin, what is the new volume of the gas? (Assume that there's no change in pressure.)

assuming the gas is ideal, we can use the Charles' Law:
V1 / T1 = V2 / T2
where
V1 = initial volume of gas
T1 = initial temp of gas
V2 = final volume of gas
T2 = final temp of gas
substituting the values to the equation,
0.20 / 333 = V2 / 533
V2 = 0.20*533/333
V2 = 0.32 cubic meter
hope this helps~ :)
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