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Find four consecutive odd integers so that five times the sum of the first and third integers excceeds four times the sum of the second and last integers by 14.

  • algebra -

    let the integers be n-3, n-1, n+1, n+3

    5(n-3 + n+1) = 4(n-1 + n+3)+14
    5(2n-2) = 4(2n+2)+14
    10n-10 = 8n+22
    2n = 32
    The numbers are 13,15,17,19

    5(13+17) = 150
    4(15+19)+14 = 150

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