Two people are talking at a distance of 2.49 m from where you are, and you measure the sound intensity as 1.47 · 10–7 W/m2. Another student is 4.79 m away from the talkers. What sound intensity does the other student measure?
To find the sound intensity measured by the other student who is 4.79 m away from the talkers, we can use the inverse square law, which states that the intensity of sound decreases as the distance from the source increases.
The inverse square law equation for sound intensity is:
I2 = I1 * (r1 / r2)²
Where:
I1 is the initial sound intensity (given as 1.47 · 10–7 W/m^2 in this case),
I2 is the sound intensity being measured,
r1 is the initial distance (2.49 m),
r2 is the distance being measured (4.79 m).
Let's substitute the given values into the equation and solve for I2:
I2 = (1.47 · 10–7 W/m^2) * (2.49 m / 4.79 m)²
Calculating this expression:
I2 = (1.47 · 10–7 W/m^2) * (0.519)²
≈ 1.47 · 10–7 W/m^2 * 0.269
≈ 3.95 · 10–8 W/m^2
Therefore, the other student measuring the sound from a distance of 4.79 m would measure a sound intensity of approximately 3.95 · 10–8 W/m^2.