A police man is driving a car with a speed of 30km/h,and firing a bullet having a speed of 150m/s towards another car which is moving ahead with a speed of 192km/f.At what speed will the bullet hit the car?

v1=30km/h =30000/3600 =8.33 m/s,

v2=150m/s,
v3= 192km/h =192000/3600=53.33 m/s.
v=?
v= v1+v2 =8.33+150m/s=158.33 m/s.

To determine the speed at which the bullet hits the car, we need to consider the relative velocities of both the police car and the other car.

Let's convert the speeds to meters per second (m/s) for consistency:

Speed of police car = 30 km/h = 30 * (1000 m/1 km) * (1 h/3600 s) ≈ 8.33 m/s
Speed of other car = 192 km/h = 192 * (1000 m/1 km) * (1 h/3600 s) ≈ 53.33 m/s
Speed of bullet = 150 m/s

The relative velocity of the police car with respect to the other car is the difference between their velocities:

Relative velocity = Speed of other car - Speed of police car
= 53.33 m/s - 8.33 m/s
= 45 m/s

The bullet's speed is independent of the police car's speed. Therefore, the bullet will hit the other car with a speed of 45 m/s.