posted by tina .
95.0 g of0.0 degrees celsius ice is added to exactly 100 g of water at 60.0 degrees celsius. when the temperature of the mixture first reaches 0.0 celsius the mass of the ice present is?
Temperature of water must decrease by 60C; how much energy is lost by the water in doing so?
mass H2O x specific heat H2O x 60 = approximately 25,000
How much can we get from 95g ice melting? That is
95 x 334 J/g =about 32,000
The differeence is 32,000-25,000 = about 7,000 and 7000/334 = 21. Approximately 21 g ice did not melt.
I estimated here and there; you need to go through and redo the problem more accurately.