Write the balanced equation for the neutralization reaction between H2SO4 and KOH in aqueous solution. Phases are optional.
H2SO4 + 2KOH ==> K2SO4 + 2H2O
To write the balanced equation for the neutralization reaction between H2SO4 (sulfuric acid) and KOH (potassium hydroxide) in aqueous solution, you need to follow a few steps:
Step 1: Write the chemical formulas for the reactants.
H2SO4 + KOH
Step 2: Identify the products of the reaction.
The reaction between an acid and a base typically results in the formation of a salt and water. In this case, sulfuric acid (H2SO4) and potassium hydroxide (KOH) will react to form potassium sulfate (K2SO4) and water (H2O).
Step 3: Write the chemical formula for the products.
K2SO4 + H2O
Step 4: Balance the equation by adjusting the coefficients of the reactants and products to ensure the same number of atoms of each element on both sides of the equation.
H2SO4 + 2KOH → K2SO4 + 2H2O
So, the balanced equation for the neutralization reaction between H2SO4 and KOH in aqueous solution is:
H2SO4 + 2KOH → K2SO4 + 2H2O
The balanced equation for the neutralization reaction between H2SO4 and KOH in aqueous solution can be written as:
H2SO4 + 2KOH -> K2SO4 + 2H2O
Here, sulfuric acid (H2SO4) reacts with potassium hydroxide (KOH) to form potassium sulfate (K2SO4) and water (H2O).