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a stone is thrown upward from the ground with a velocity of 80 m/s. how long will it take to reach a point 3 m above the ground on its way down?

  • Physics -

    The max height is
    H= v²/2g =80²/2•9.8 = 326.53 m.
    The time of upward motion is
    t1 =v/g =80/9.8=8.16 s,
    the time of downward motion is
    t2=sqrt{2(H-h)/g}=sqrt{2(326.53-3)/9.8} =8.126.
    The total time is
    t=t1+t2 =8.16+8.126 =16.126 s.

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