posted by .

The motion of a block-spring system is described by x(t) = A sin(ùt). Find ù, if the potential energy equals the kinetic energy at t = 6.11 s.

I'm really not sure how to solve this. It seems that you need more information, either x or A? I appreciate any help, thank you!

  • Physics -

    Potential eneregy equals kinetic energy in a simple-harmonic-motion system when the phase angle (measured from the zero-deflection position) is pi/4 radians (or 3 pi/4 or 5 pi/4 or 7 pi/4)

    If 6.11*ù = pi/4, then
    ù = 0.1285 s^-1 is one possibility

  • Physics -

    Thank you for your help!

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. PHYSICS helppppp

    A 0.2 kilogram baseball is thrown vertically downwards towards to the same horizontal floor. The baseball possesses an initial velocity of 30 meters per second. The height is 10.00m. (A) Calculate the POTENTIAL GRAVITATIONAL ENERGY …
  2. Physics Problem

    A 3.00-kg mass is fastened to a light spring that passes over a pulley. They pulley is frictionless, and its inertia may be neglected. The mass is released from rest when the spring is unstretched. If the mass drops 10.0cm before stopping, …
  3. physics # 9

    9. A block attached to a spring of negligible mass undergoes simple harmonic motion on a frictionless horizontal surface. The potential energy of the system is zero at the equilibrium position and has a maximum value of 50 J. When …
  4. physics

    I'm given a spring that has a mass of 100 g and a constant of 22 N/m with an A of 5 cm I belive the A is amplitude and I'm asked for the Total Energy which i don't know how to do the max velocity also have no idea how to do and the …
  5. Physics

    The motion of a particle connected to a spring is described by x=10cos(πt). At what time (in s) is the potential energy equal to the kinetic energy?
  6. Physics

    I need help with part b, c, and d please! A 45 g mass is attached to a massless spring and allowed to oscillate around an equilibrium according to: y(t) = 1.4 * sin( 4 * t ) where y is measured in meters and t in seconds. -------------------------------------------------------------------------------- …
  7. Physics

    I need help with b... I found that k=.750880 for part a but I can't figure out what y would be to get potential energy. A 52 g mass is attached to a massless spring and allowed to oscillate around an equilibrium according to: y(t) …
  8. physics (simple harmonic motion)

    If the phase angle for a block-spring system in SHM is π/5 rad and the block's position is given x = xm cos(ωt + ϕ), what is the ratio of the kinetic energy to the potential energy at time t = 0?
  9. Physics

    A thrill-seeking cat with mass 4.00 kg is attached by a harness to an ideal spring of negligible mass and oscillates vertically in SHM. The amplitude is 0.050 m, and at the highest point of the motion the spring has its natural unstretched …
  10. Physics

    In a horizontal spring-mass configuration, the position of the 0.52 kg mass is described by [x = (1.09 m) sin(2.70t)] a) What is in meters the amplitude of these oscillations?

More Similar Questions