# Integrated Math 1

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Suppose a parabola has its vertex at (0, 1) and its zeros at x = -2 and x = 2. Then equals _____.
A. 1-1/4x^2
B. 4-x^2
C. X^2-1
D. X^2-4

• Integrated Math 1 -

The vertex is at (0,4) sorry, I copied it wrong.

• Integrated Math 1 -

since the vertex is above the x-axis, we will have (with a > 0)

y = -a(x-h)^2 + k

We know (h,k) = (0,4), so

y = -ax^2 + 4

Since y(2) = 0, 0=-4a+4, so a=1

y = -x^2 + 4, so (B)

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