physics
posted by Danielle .
A ball of mass 0.440 kg moving east (+x direction) with a speed of 3.80 m/s collides headon with a 0.600 kg ball at rest. If the collision is perfectly elastic, what will be the speed and direction of each ball after the collision?

Let
u=vel. before, and
v=vel. after collision
velocities are positive in +x direction.
Momentum is conserved for elastic and nonelastic collisions:
∑mu = ∑mv
If the collision is perfectly elastic, then kinetic energies are conserved before and after collision :
∑ (1/2)mu² = ∑(1/2)mv².
Since all velocities before collision are known, there are two equations to solve for two unknowns, v1 and v2.
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