how do you find the domain in 2/x^2+3?
pls help
Range: The range is the set of all possible output values , which result from using the function formula.
In this case when x = 0
2 / x ^ 2 -> infinity.
So domain : ( -infinity , 0 ] U [ 0 , infinity )
Or all value of x different of 0
Domain: The domain of a function is the set of all possible input values which allows the function formula to work.
To find the domain of a function, we need to determine the values that the input variable (in this case, x) can take on.
In the given function, 2/x^2 + 3, the only potential issue is if the denominator, x^2, becomes zero. Division by zero is not defined, so we need to exclude any values of x that make the denominator zero.
To find these values, we set the denominator equal to zero and solve for x:
x^2 = 0
Taking the square root of both sides, we find:
x = 0
So, x = 0 is not included in the domain of the function.
Therefore, the domain of the function 2/x^2 + 3 is all real numbers except x = 0. In interval notation, this can be represented as (-∞, 0) U (0, ∞).