Calculus

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Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region.
2y=5x^(1/2) , y=4 and 2y+1x=6

I've been trying this problem for about 3 hours.
Please help!!!!!

  • Calculus -

    The region of interest is a triangle-ish area. The intersections are
    (-2,4) (64/25,4) (1,5/2)

    wrt x, divide region into two parts:

    ∫[-2,1] 4 - (6-x)/2 dx
    + ∫[1,64/25] 4 - 5/2 √x dx
    = 9/4 + 27/25 = 333/100

    wrt y,

    ∫[5/2,4] 4/25 y^2 - (6-2y) dy
    = 333/100

  • Calculus -

    Thank you so much!!!!!

  • Calculus -

    no sweat. Hang in there and after a few hundred more of these, they'll be a piece of cake!

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